Science, asked by savarnnaina, 6 months ago

A percolation pipe is filled with soil A. Water (50ml) is then poured steadily onto the
surface of the soil.
(i) It takes 10minutes from the start of pouring for the water to disappear below the
surface of the soil. What is the percolation rate for soil A?
(ii) After the water has fully drained from the soil A, the sample is weighed. This wet
weight is 25.8g. After drying in an overnight, the soil sample is weighed again. The
dry weight is 22.3g. What is the water-holding capacity of the soil?
please give the answer fast

Answers

Answered by akshat3472
9

Answer:

50 ml is the answer of this question

Answered by rudranshpatra227
12

1) 50ml ÷ 10min = 5% rate

2) 25.8 -22.3 = 3.5

25.8 × 3.5 = 90.3 capacity

process!!

1) time = 10min

volume of water = 50

so, volume of water ÷ time = % rate

2) the current water - the left water = 3.5

after that, 25.8 × 3.5 = 90.3 capacity

I AM NOT SURE IF ITS CORRECT BUT THE PROCESS IS CORRECT!!!! BOIIII

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