Question

A perfect gas at 27c heated at
constant pressure so as to double its
volume The
temperature of the gas will
be

(a) 127c
(b) 527c
(c) 381c
(d) 327c


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Answer 1

V1=V(say), where V is the initial volume of the gas. Therefore, V2=2V since final volume is double the initial volume. T2=? Solving, we get T2=final temperature of the gas=600K or (600–273)degree C or 327 degrees C.

Answer 2

(d). 327 C

Explanation:

let volume 1 be x ,as the volume gets doubled after heating therfore let the volume after heating be 2x

let temp. 1 =27c=300k , temp. 2 =?

by charles law

V1/T1 = V2/T2

x/300 =2x/T2

T2= 600k

T2=600k-273k

T2= 327c