A perfect gas at 340 K is heated at constant pressure until its volume has increased by 18 per cent. What is the final temperature of the gas?
Answers
Answered by
15
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
==================================
Answered by
3
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================
Given Informations are listed below :
T1 = 340 K
V1 = V (say)
T2 = ?
V2 = V + 18V/100 = 59 V/50
Also, it is mentioned that pressure is constant. So, it is CHARLES' LAW.
BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> V/340 = (59V/50)/T2
=> 50 × T2 = 59 × 340
=> T2 = (2006/5) K = 401.2 K [Ans.]
==================================
⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐
Similar questions