Question

A perfect gas goes from state A to another
state B by absorbing 8 x 10° J of heat and doing
6.5x10% J of external work. It is now transferred
between the same two states in another process
in which it absorbs 100 J of heat. Then in the
second process :-
Work done on the gas is 0.5 x 10% J
(2) Work done by gas is 0.5 x 105 J
(3) Work done on gas is 10% J
(47 Work done by gas is 105 J​

Answer 1

Dear Student,

◆ Answer -

Work done on the gas is 50 J

● Explanation -

In first process,

q = W + ∆U

∆U = q - W

∆U = 8×100 - 6.5×100

∆U = 800 - 650

∆U = 150 J

In second process,

q = W + ∆U

W = ∆U - q

W = 150 - 100

W = 50 J

Hence, work done on the gas is 50 J.

Thanks dear. Hope this helps you...