Question

A perfect smooth sphere A of mass 2 kg is in contact with a rectangular block B of massand vertical wall as shown in the figure. All surfaces are smooth. Find normal reactionvertical wall on sphere A​

Answer 1

Answer:

I cannot see the figure

Explanation:

sorry bruh

Answer 2

Mg=2Rsin37

R=Mg/2sin37

R=Mg / 2*3/5    ( sin 37=3/5 is given)

therefore , R=5Mg/6

this sphere is lying  between  2 inclined planes so there are 2 normal reactions on the sphere by the plane. if we resolve these reactions the vertical forces will be Rsin37*2 this system is under  equllibrium so verical forces 2Rsin37 is equal to weight of the sphere Mg (here assume normal reaction= R)