A perfect square can never have the following digit in its one's place. *
(a) 4
(b) 7
(c) 0
(d) 5
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Answer:
7
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2
Answer
The answer is 7.
(b) 7.
Step by step explanation
If you find out the square of the first 10 digits (1-10) then you will see that none of the squares found have 7 in their ones digit.
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