A perfect square can never have which of the following digit at ones place
1) 1
2) 6
3) 5
4) 3
Answers
Answered by
0
Answer:
We know that, a number ending with digits 2, 3, 7 or 8 can never be a perfect square. Clearly, a perfect square can never have the digit 8 in its one's place
Step-by-step explanation:
Answered by
1
Answer:
3
Step-by-step explanation:
It can have other digits at ends as...
1) 9^2 = 81
2) 4^2 = 16
3) 5^2= 25
I hope this will help you
Similar questions