Math, asked by neelakapadiya, 10 months ago

a perfect square number has four digits none of which is 0 the digit from left to right have values that are : even, even,odd,odd find the number​

Answers

Answered by Anonymous
8

Answer:

8836

Step-by-step explanation:

Given  

A perfect square number has four digits none of which is zero. The digits from left to right have values that are even, even, odd , even .find the...

ANSWER

 Suppose a b c d is a perfect square, where a = even number, b = even number, c = odd number and d = even number.

The square root of the smallest four digit number is 32 x 32 = 1024 and largest four digit number is 99 x 99 = 9801. So the number is anywhere between 32 and 99. The unit place number is even, so it will be the square of an even number. So it can be 32, 34, etc. The left digit has to be 2, 4, 6, 8.

Again the squares will be in the range 48 to 94. So 94 satisfies the given condition.

So 8836 will be the number. It is 94 x 94 = 8836

So it is even, even, odd , even

hope it helps you ♥️♥️

with regards @ARSH☺️☺️

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