A perfect square number has four digits none of which is zero. The digits from left to right have values that are even, even, odd , even .find the number
Answers
Answer:
8836
Step-by-step explanation:
A perfect square number has four digits none of which is zero. The digits from left to right have values that are even, even, odd , even .find the number
8836 is the number meeting all requirements
8836 = 94²
Below is the list of all the numbers & their square ending up in 4 digits
Number Square
32 1024
33 1089
34 1156
35 1225
36 1296
37 1369
38 1444
39 1521
40 1600
41 1681
42 1764
43 1849
44 1936
45 2025
46 2116
47 2209
48 2304
49 2401
50 2500
51 2601
52 2704
53 2809
54 2916
55 3025
56 3136
57 3249
58 3364
59 3481
60 3600
61 3721
62 3844
63 3969
64 4096
65 4225
66 4356
67 4489
68 4624
69 4761
70 4900
71 5041
72 5184
73 5329
74 5476
75 5625
76 5776
77 5929
78 6084
79 6241
80 6400
81 6561
82 6724
83 6889
84 7056
85 7225
86 7396
87 7569
88 7744
89 7921
90 8100
91 8281
92 8464
93 8649
94 8836
95 9025
96 9216
97 9409
98 9604
99 9801
Answer:
8836
Step-by-step explanation:
Given
A perfect square number has four digits none of which is zero. The digits from left to right have values that are even, even, odd , even .find the...
ANSWER
Suppose a b c d is a perfect square, where a = even number, b = even number, c = odd number and d = even number.
The square root of the smallest four digit number is 32 x 32 = 1024 and largest four digit number is 99 x 99 = 9801. So the number is anywhere between 32 and 99. The unit place number is even, so it will be the square of an even number. So it can be 32, 34, etc. The left digit has to be 2, 4, 6, 8.
Again the squares will be in the range 48 to 94. So 94 satisfies the given condition.
So 8836 will be the number. It is 94 x 94 = 8836
So it is even, even, odd , even