Physics, asked by kadamrushikesh8642, 3 months ago

A perfectly black surface emits radiant energy of 3 x 10^5 J at a temperature 400 K . Energy radiated by another surface with e= 0.4 of same area in the same time and at same temperature is​

Answers

Answered by Anonymous
1

Answer:

We know that emissive power is given as: E=σεAT

4

E=5.7×10

−8

×400

4

=1459.2J

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