A perfectly reflecting mirror has an area of
1 cm². Light energy is allowed to fall on it for an
hour at the rate of 10 Wcm 2. The force that acts on
the mirror is
(a) 3.35 x10-'N (b) 6.7x10-N
(c) 3.35 x10-N (d) 6.7x10-8N
Answers
Answered by
3
Explanation:
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.......
Answered by
2
Answer:
Option D
Let n photons fall on mirror each having frequency ν1
energy of all photons is 1 sec is = 10 J nν
Rate of change of momentum =
2nh
v/c
(after reflection)
=
HOPE IT'S CORRECT
HAPPY KNOWLEDGE!
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