Question

A perimeter of a rectangle 54cm and lenght 14cm then find the area of rectangle​

Answer 1

Answer:

perimeter=54

2(l+b)=54

l+b=27

14+b=27

b=13

area of rectangle=lb

=14*13

=182

Answer 2

The Area is "182 cm²" and the breadth is "13 cm".

Step-by-step explanation:

$The \ given \ values \ are:\\The \ perimeter \ of \ a \ rectangle,P=54 \ cm\\The \ length,L=14 \ cm\\The breadth,B=?\\The \ area,A =?\\As \ we \ know,\\The \ perimeter \ of \ a \ rectangle,P=2(L+B)\\So,\\54=2(14+B)\\\frac{54}{2}=14+B\\ 27=14+B\\B=27-14\\B=13 \ cm\\Now,\\The \ Area \ of \ a \ rectangle,A= L\times B\\On \ putting \ the \ values \ in \ the \ above \ formula,we \ get\\A=14\times 13\\A=182 \ cm^2$

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