a perimeter of isosceles triangle is 30cm and two of its equal sides measure 12cm. find the area of triangle
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Here's ur solution :
Let the other side be 'x'
We know that -
perimeter of Isosceles ∆
= sum of all sides.
Other two sides are 12 and 12.
Finding the value of x
Area of Isosceles ∆
Finding area
calculation in the attachment.
Hence, area = 9√15 cm²
Hope it helps ✔
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Answer:
Step-by-step explanation: perimeter of triangle ABC = 30 cm = AB + BC + CA
AB + BC + CA = 30
LET AB and BC are equal sides of the triangle
AB and BC = 12cm
12 +12+ CA = 30
CA = 6cm
Area of triangle ABC equals to √ s ( s-a)( s- b)( s- c)
s =30/ 2 =15
√ 15 ( 15 - 12 )(15-12)(15-6)
√15 ×3×3×9
√1215
=. 9√15
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