Question

a] Perimeter of square is 500 cm, find 4s area.
Expand (7m - 4)²​

Answer 1

To Find:

• Find area of Square whose Perimeter is 500 cm
• Expand (7m - 4)²

Solution:

• If perimeter is 500 then,

$\sf 4(side) = 500 \\ \sf \: side = \frac{ \cancel{500} \: 125}{ \cancel 4 \: 1} = 125 \\ \sf \: Area = {(side)}^{2} = {(125)}^{2} = 15,625 \\ \\ \boxed{ \sf Area = 15,625 \: {cm}^{2} }$

• We can use formula for finding expansion

$\sf \: {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ \sf \: now \\ \sf \: {(7m - 4)}^{2} = {(7m)}^{2} - 2(7m)(4) + {(4)}^{2} \\ \boxed{\sf {(7m - 4)}^{2} = 49 {m}^{2} - 28m + 16}$

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@ItsRuchikahere

Answer 2

Step-by-step explanation:

If the perimeter is 500 then,

the side is

P = 4 X s

500 = 4 X s

500/4 = s

125 = s

Area = s X s

Area = 125 X 125

Area = 15625 $cm^{2}$

It is known that, $(a-b)^{2}$ = $a^{2} - 2ab^{2} + b^{2}$

$(7m-4)^{2} \\= (7m)^{2} - 2 X (7m) X (4) + (4)^{2} \\= 49m^{2} - 56m +16$

Thank You

Hope it Helps....