Question

A perpendicular drawn from the centre of a circle on its chord bisects the chord,
Complete the following activity to prove it.
Given: Seg AB is a chord of a circle with centre 0.
seg OP I chord AB.​

Answer 1

Answer:

AB is chord of a circle with centre O and OD⊥AB. We have to prove that AD = DB

In △ODA and △ODB

OA=OB (radii)

OD=OD (common)

∠ODA=∠ODB=90

∘

(OD⊥AB)

△ODA=△ODB(RHS)

AD=DB[C.P.C.T]