Question

A perpendicular force of 50 N is acting on a circular plate of radius 7cm.
The pressure acting on plate will be

Answer 1

Given:

F=50N

$area = \pi {r}^{2} \\ \: \: = \frac{22}{7} \times 7 \\ = 22 {cm}^{2}$

solution:

P=F/A

=50/22

=2.27 Pa

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Answer 2

The pressure acting on plate will be 3246.75 Pa.

Explanation:

The pressure acting on an object is given as

$P=\frac{F}{A}$

Here, F is the force acting on an object and A is area.

As the object is a circular plate of radius of 7 cm = 0.07 m.

So, its area

$A=\pi r^2$

$A=\frac{22}{7} \times(0.07m)^2=0.0154m^2$

Given F = 50 N.

Substitute the given values, we get

$P=\frac{50 N}{0.0154m^2}$

P = 3246.75 Pa

Thus, the pressure acting on plate will be 3246.75 Pa.

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