A person 2 meters tall walks directly away from a streetlight that is 8 meters above the ground. if the person is walking at a constant rate and the person's shadow is lengthening at the rate of meters per second, at what rate, in meters per second, is the person walking?
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The person is around 2 meters tall and the street light is only 8 meters above the ground. The rate at which the person is walking is 4/3
Step-by-step explanation:
- We find the answer by using the equation ds/dt which equals to 4/9.
- s represents the length of the shadow while x represents distant of shadow from the street light.
- Hence we get x/6 = s/2 so dx/dt putting the values we get 6ds/2dt and the answer is 4/3
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