Question

A person 25m away from cell tower observes the top of tower at an angle of elevation 30 find height of tower

Answer 1

Answer:

Step-by-step explanation:

let the height of the tower 'AB'  be = h

θ = 30°

base 'BC' = 25 m

tanθ = perpendicular/base

tan 30° = AB/ BC

$\frac{1}{\sqrt{3} }$ = $\frac{AB}{25}$

AB= $\frac{25}{\sqrt{3} }$