a person a borrowed rupees 40000 at 10% per annum for 2 years after a person be borrowed rupees 50000 at 12% per annum how many years after revolving of person be the amount of interest of both of them will be equal?
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Answer:
Sum borrowed (P) = ₹40000
Rate (R) = 10% p.a. compounded annually
Time (T) = 2 years
∴ Interest for first year = PRT/100
= ₹ (40000 × 10 ×1)/100 = ₹ 4000
Amount after one year = ₹ 40,000 + 4000 = ₹44000
Principal for the second year = ₹44000
∴ Interest for the second year
= (44000 × 10 ×1)/100 = ₹ 4400
∴ C.I. Interest for 2 years = ₹4000 + 4400
= ₹ 8400
In second case,
Principal (P) = ₹40000
Rate (R) = 10.5% p.a.
Time (T) = 2 years
∴ S.I. Interest = PRT/100 = (40000 × 10.5 ×2)/100
= ₹ (40000 × 105 × 2)/(100 × 10) = ₹8400
In both the cases, interest is same.
Step-by-step explanation:
PLS MARK AS BRILLIANT AND PLS FOLLOW
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