A person A can paint a house in 30 days. A second person B can paint the same house in 36
days. Both A and B work together for 15 days. Then, A goes away. The number of days that
B takes to complete the painting is (in days)
armyboy56:
3 days
Answers
Answered by
93
Hey Buddy
Here’s the answer
——————————————
# we’ll be solving this question with L.C.M. method
=> Now taking L.C.M. of 30 and 30
=> L.C.M. = 180 unit
So
A complete = 180/30 = 6 unit/day
B complete = 180/36 = 5 unit/day
If A and B work together
They complete = 6 + 5 = 11 unit/day
A.T.Q.
They work together for 15 days , so work competed
=> 11 * 15
=> 165 unit
Now work left = 180 - 165 = 15 unit
Further , A goes away and now B have to complete 15 unit work . And it will be completed in
=> 15 / 5
=> 3 days
HOPE HELPED
PEACE :)
Here’s the answer
——————————————
# we’ll be solving this question with L.C.M. method
=> Now taking L.C.M. of 30 and 30
=> L.C.M. = 180 unit
So
A complete = 180/30 = 6 unit/day
B complete = 180/36 = 5 unit/day
If A and B work together
They complete = 6 + 5 = 11 unit/day
A.T.Q.
They work together for 15 days , so work competed
=> 11 * 15
=> 165 unit
Now work left = 180 - 165 = 15 unit
Further , A goes away and now B have to complete 15 unit work . And it will be completed in
=> 15 / 5
=> 3 days
HOPE HELPED
PEACE :)
Answered by
40
LCM method
LCM=180
A = 6unit / day
B = 5 unit /day
A+ B = 11/unit /day
if they work for 15 day , work completed
15×11
165 unit
work left
180 - 165
15 unit
B have to complete it
15/5
3 days
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