Question

A person 'A' is walking on a trolley with an acceleration of 2 m/s2. The mass of the person is 50 kg. The trolley is being moved on a platform with velocity of
-3 m/s and the platform is moving on ground with an acceleration of _5i m/s2. Then the pseudo forces on person when viewed from trolley, platform and
ground are respectively :-
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Answer 1

Answer:

1 hour lol lol lolloljgih

Answer 2

solution :

let, M be the mass of person, A

    a1 be the acceleration of person, A

    a2 be the acceleration of trolley

    a3 be the acceleration of platform

here, M = 50 kg

        a1 = 2 m/s^2

        a2 = -3m/s / 1s = -3 m/s^2

        a3 = 5m/s^2

as we can see the direction of the motions from the sign of accelerations of the person , trolley and platform.

now, pseudo forces on the person be

F1 = M*a1 = 50*2 = 100N

F2 = M*a2 = 50*(-3) = -150N

F3 = M*a3 = 50*5 = 250N