A person apply force of 100 N for 10m, then he is tired and forced linerly reduced to 50 N in next 10 m . If the friction is constant find the work done by applid force. and. work done by friction
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Answer:
Answer is 1000 joules
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The plot of the forces applied b the woman and the frictional forcesf versus displacement is,
x=20m,f=50N(
=0)
Since we have f=∣f∣=50N
It opposes the motion and acts in the direction opposite to f,
So, the negative side of the force axis,
The work-done by the woman is:
W
f
=area of rectangle ABCD+area of trapezium CEID
W
f
=1000×10+
2
1
(1000+50)×10
1000+750=1750J
Now, the work done by the frictional force is:
Area of the rectangle AGHI
W
f
=(−50)×20=1000N
Explanation:
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