Physics, asked by prashad98640, 7 months ago

A person approaches a plane mirror with velocity V then relative velocity of approach of person and his image is,

Answers

Answered by anmoldeep234
0

the velocity of both will be same

Answered by nirman95
1

Given:

A person approaches a plane mirror with velocity V.

To find:

Relative velocity of approach of person and his image.

Calculation:

Let's assume that person is approaching the mirror along + x axis ;

So, his Velocity can be represented as :

 \rm{ \vec{v}_{o}  = v \:  \hat{i}}

Since , the magnitude of Velocity of image formed by plane mirror will be same (but in opposite direction) , the velocity of image will be :

 \rm{ \vec{v}_{i}  = v \:  ( - \hat{i})}

So, Velocity of approach will be :

 \therefore \:  \rm{\vec{v}_{o} - \vec{v}_{i} =  v \hat{i} -  \{ v( -  \hat{i}) \}}

 =  >  \:  \rm{\vec{v}_{o} - \vec{v}_{i} =  v \hat{i} -  \{  - v  \hat{i} \}}

 =  >  \:  \rm{\vec{v}_{o} - \vec{v}_{i} =  v \hat{i}  +  v  \hat{i}}

 =  >  \:  \rm{\vec{v}_{o} - \vec{v}_{i} =  2v \hat{i}  }

So, Velocity of Approach is :

 \boxed{ \bf{ \red{ \large{\vec{v}_{o} - \vec{v}_{i} =  2v \hat{i}}}}}

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