Math, asked by jordandiaz87, 11 months ago

A person ate a third of a box of chocolates. There are now 16 left. How much were in the box at the start​?

Answers

Answered by frarhlote
0

Answer:

12

Step-by-step explanation:

if u ate 1/3 of the box, 2/3 are left.

lets x equal the original number.

if 2/3x=16

than 2x=48

and x=12

Answered by anishakant5
0

Answer:

let the total boxes be x

a/q

2/3rd of x = 16

2/3x = 16

2x = 16×3

2x = 48

x = 48/2

x = 24

no. of boxes at the start = 24 - 16 = 8

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