Question

A person borrowed a certain sum at 6% interest per annum and immediately lent the same to another person at 10% interest per annum. He gained Rs.1200 in 6 months. What is the sum the person borrowed?​

Answer 1

Answer:

24000

Step-by-step explanation:

if he gains 1200 in 6 months. for 12 months it will be 2400 by looking 10% of 24000 is 2400 so he borrowed 24000

Answer 2

Final Answer:

The sum that the person borrowed  at 6% interest per annum and lent  to another person at 10% interest per annum, is Rs. 60,00,000.

Given:

A person borrowed a certain sum at 6% interest per annum and immediately lent the same to another person at 10% interest per annum. He gained Rs.1200 in 6 months.

To Find:

The sum the person borrowed  at 6% interest per annum.

Explanation:

The following points are notable to get at its solution.

• The formula for the Simple Interest is

$=\frac{PTR}{100}$

• This formula calculates the Simple interest (S.I) earned on the  principal (P) that is deposited at the annual rate of interest (R) applied for the particular tenure or time period (T).
• The six months is equivalent to $=\frac{1}{2} =0.5\;year$.

Step 1 of 3

Assume that the sum borrowed  by the person at 6% interest per annum is Rs.$x$.

So, the SI on Rs.$x$  at 6% interest per annum for 6 months (in Rs.) is

$=\frac{x\times 0.5 \times 0.06}{100} \\=\frac{3x}{10000}$

Step 2 of 3

It is evident that the sum that the person borrowed  at 6% interest per annum is equal to that lent  to another person at 10% interest per annum.

So, the SI on Rs.$x$  at 10% interest per annum for 6 months (in Rs.) is

$=\frac{x\times 0.5 \times 0.10}{100} \\=\frac{5x}{10000}$

Step 3 of 3

Now, write the following equation and solve it.

$\frac{5x}{10000}-\frac{3x}{10000}=1200\\5x-3x=1200\times10000\\2x=12000000\\x=Rs.\;60,00,000$

Therefore, the required sum that the person borrowed  at 6% interest per annum and  lent  to another person at 10% interest per annum, is Rs. 60,00,000.

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