Question

A person borrows $ 6000 at 8 p.c.p.a simple interest for 8 months .After 8 months he returns​

Answer 1

Answer:

6032 rs

Step-by-step explanation:

Principal Amount = 6000rs

Rate = 8%

Time = 8 months = 8/12=2/3 year

$intrest = \frac{p \times r \times t}{100} \\ \frac{600 \times 8 \times 2}{100 \times 3} \\ 32rs$

Compound Amount after 8 month =

principal+intrest

6000+32=6032rs

Answer 2

Answer:

• The person has to pay $ 6320 after the end of 8 months.

Step-by-step explanation:

Given that:

• A person borrows $ 6000 at 8 % per annum for 8 months at simple interest.

As we know that:

$\sf{SI=\dfrac{P\times R\times T}{100}}$

Where,

• P = Principal
• R = Rate
• T = Time

As we know that,

$\sf{8\;months=\dfrac{8}{12}\;years=\dfrac{2}{3}\;years}$

Substituting the values,

$\sf{SI=\dfrac{6000\times 8\times 2}{100\times3}}$

Cutting off the zeros,

$\sf{\longrightarrow \dfrac{60\!\!\!\not{0}\!\!\!\not{0}\times 8\times 2}{1\!\!\!\not{0}\!\!\!\not{0}\times3}}$

$\sf{\longrightarrow \dfrac{60\times 8\times 2}{1\times3}}$

Reducing the numbers,

$\sf{\longrightarrow \dfrac{20\times 8\times 2}{1\times1}}$

$\sf{\longrightarrow 20\times 8\times 2}$

Multiplying the numbers,

$\sf{\longrightarrow 320}$

Hence, SI = $320

Now,

As we know that,

• Amount = Principal + SI

Substituting the values,

Amount = $(6000 + 320)

= $6320

Hence, the person returns $6320 after 8 months.

Abbreviations Used:

• SI = Simple Interest