Question

a person borrows rs 15000 partly at 10 % and remaining at 12% if at the end of 2 and half years he pays a total simple interest rs 4050 how much did he borrow at each rate​

Answer 1

Answer:

P

2

=15,000r=12%t=2years

I

1

=

100

P

2

×R

1

×T

=

100

15000×12×2

=3600

P=P

2

r

2

=15%t=2years

I

2

=

100

P

1

×R

2

×t

=

100

P

2

×15×2

Totalenterest I = 9000

I = I

1

+I

2

9000=3600+

100

P

2

×15×2

9000−3600=

100

P

2

×30

30

5400

×100=P

2

P

2

=18000Ans.

15000+18000=33000

Answer 2

Let consider Rs P was borrowed at 10% per annum, and Rs( 15000-P)  12% per annum.

According the question :-

[{(P × 2.1/2 ×10)}÷ 100]  +[{ ( 15000 - P) × 2.1/2 ×12} ÷100] = 4050

⇒[ (P×$\frac{5}{2}$ × 10) ÷ 100 ] + [ { ( 15000 - P) ×$\frac{5}{2}$ × 12} ÷ 100] = 4050

⇒ 25P + 450000 - 30P = 4050 × 100

⇒450000 - 5P = 405000

⇒450000 - 405000= 5P

∴P = 45000 ÷5 = 9000

Hence the person borrowed Rs9000.

Ans :-  The person borrowed Rs9000  at each rate.

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