Question

a person bought a horse and a vehicle for Rs 40000. he sold horse at 5% loss on the whole transaction he got profits of 1% find cp of horse?
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Answer 1

solution:- Total CP of a horse and a carriage = $ 40,000.

Suppose the C.P. of horse be $ y, then

C.P. of carriage = $ (40000 – y)

Then,

∴110 × y+(40000 - y) × 95=40000 × 101100100100

⇒ 110y + 3800000 – 95y = 4040000

⇒ 15y = 4040000 – 3800000

⇒ 15y = 240000

⇒ y =240000= $ 1600015

Answer 2

Answer:-

Total CP of Horse and Vehicle = 40,000.

SP of these two = 40000 + 1% of 40000 = 40400.

Let Cp of Horse was X and Vehicle was Y. Then

X + Y = 40000.

Y = 40000 - X ----------- (1)

SP of Horse = X + 10% of X = 1.1X

SP of Vehicle = Y - 5% of Y = 0.95Y.

Total SP = 40400

1.1X + 0.95Y = 40400

Using Equation 1.

1.1X + 0.95 * (40000 - X) = 40400

1.1X + 38000- 0.95 = 40400

0.15X = 40400 - 38000

X = 2400/0.15 = Rs. 16000.

CP of the Horse = Rs. 16000.

Hence,the cp of the horse is Rs. 16000.