A person bought pens and pencils total worth rs.564/-each pen costs rs.7/-,each pencil costs rs.3/-,total things are108 no's how many of each type did he buy
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total cost=Rs.564
let,no.of pens be x
no.of pencils be y
total no.of things =108
cost of pens = Rs.7x
cost of pencils=Rs.3y
⇒7x+3y=564-----------eq.1
⇒x+y=108------------eq.2
eq.2 is multiplied by 3
⇒3x+3y=324--------------eq.3
eq.1 is subtracted by eq.3
⇒4x=240
⇒x=60
substitute x=60 in eq.2
⇒60+y=108
⇒y=108-60
⇒y=48
let,no.of pens be x
no.of pencils be y
total no.of things =108
cost of pens = Rs.7x
cost of pencils=Rs.3y
⇒7x+3y=564-----------eq.1
⇒x+y=108------------eq.2
eq.2 is multiplied by 3
⇒3x+3y=324--------------eq.3
eq.1 is subtracted by eq.3
⇒4x=240
⇒x=60
substitute x=60 in eq.2
⇒60+y=108
⇒y=108-60
⇒y=48
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