Math, asked by Rjstar0639, 1 year ago

A person bought two radios in Rs. 800 & sell it one 15% profit & second in loss of 15%. What is the total selling price?

Answers

Answered by pathak3

profit of 69% loss 649

Rjstar0639: can uh tell me the solution

srandheer00p4lz53: Tell the solutions

roshankumarrshp3a7vb: 15%=15/100=3/20 in case of profit let cp=20,profit=3 n sp =23. In loss case let cp=20 loss=3 n sp=17. So total cp=40 n total sp=40 that means no profit no loss. So according to question total sp=total cp=800

Answered by wifilethbridge

Answer:

Rs.1600

Step-by-step explanation:

Radio 1 :

Cost Price = Rs.800

Profit% = 15%

Profit = $15\% \times 800$

= $\frac{15}{100} \times 800$

= $120$

SP = CP +Profit = Rs.800+Rs.120=Rs.920

So, SP of first radio is Rs.920

Radio 2 :

Cost Price = Rs.800

Loss% = 15%

Loss= $15\% \times 800$

= $\frac{15}{100} \times 800$

= $120$

SP = CP -Loss = Rs.800-Rs.120=Rs.680

So, Sp of first radio is Rs.680

So, the total selling price = Rs.920+Rs.680=1600

Hence the total selling price is Rs.1600

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