Question

A person brings a mass 2 kg from A to B. The increase in kinetic energy of mass is 4J and work done by the person on the mass is -10J.The potential difference between B and A is....... J/kg​

Answer 1

${\boxed{\sf\:{Answer}}}$ = $\dfrac{-7J}{Kg}$

$\textbf {\underline {\underline {Step\:-by\:-Step\:-Explanation}}}$

KB - KA = 4J

W = - 10 J

Now,

Energy Conservation :

KA + PA + W = Kg + PB

$\implies {PB} - {PA} = W + KB - KB$

==> $\triangle{UAB}$= (- 10) + (-4J)

$\implies {UAB} = - 14 J$

$\implies {V} = \dfrac{\triangle{U}}{m}$

==> $\triangle {VAB} = \dfrac{\triangle UAB}{m}$

==> $\dfrac {-14J}{2Kg}$

$\therefore\dfrac {-7J}{Kg}$

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