Math, asked by binnytresa4340, 9 months ago

A person buy 5 table and 9 chairs for rs 15400.he sells table at 10% profit and chairs at 20%.profit.if his total profit on selling all tables and chairs is 2080rs.find cost price 9f 3 chairs

Answers

Answered by sangeetayadab7
1

Answer:

formula of cp 100/(100 - loss%)*sp

Step-by-step explanation:

put the formula

Answered by ChitranjanMahajan
6

The cost price of 3 chairs is Rs. 1,800.

• Given,

Number of tables bought = 5

Number of chairs bought = 9

• Let the cost price of each table be x.

∴  The cost price of 5 tables = 5x

Let the cost price of each chair be y.

∴  The cost price of 9 chairs = 9y

• According to the question,

Cost of 5 tables + Cost of 9 chairs = Rs. 15400

=> 5x + 9y = Rs. 15,400 -(i)

• Also given,

Profit earned on selling 5 tables = 10 %

Profit earned on selling 9 chairs = 20 %

Total profit earned = Rs. 2,080

• Now, profit is always earned on the cost price of an article.

Therefore, if the C.P. of 5 tables is 5x, then the profit earned on their C.P. = 10 % of 5x

= (10 / 100) × 5x

= (10 × 5x) / 100

= 50x / 100

• Similarly, the profit earned on the C.P. of 9 chairs = 20 % of 9y

= (20 / 100) × 9y

= (20 × 9y) / 100

= 180y / 100

• According to the question,

(50x / 100) + (180y / 100)  = Rs. 2,080

=> ( 50x + 180y) / 100 = Rs. 2,080

=> 50x + 180y = Rs. 2,080 × 100

=> 10 ( 5x + 18y ) = Rs. 2,080 × 100

=>  5x + 18y = ( Rs. 2,080 × 100 ) / 10

=> 5x + 18y = Rs. 20,800 -(ii)

• Now, the equations (i) and (ii) can be solved simultaneously by subtracting (i) from (ii).

• Subtracting eq. (i) from eq. (ii), we get,

( 5x + 18y ) - ( 5x + 9y ) = Rs. 20,800 - Rs. 15,400

=> 5x + 18y - 5x - 9y = Rs. 5,400

=> 5x - 5x + 18y - 9y = Rs. 5,400

=>  0 + 9y = Rs. 5,400

=> 9y = Rs. 5,400

=> y = Rs. 5,400 / 9

=> y = Rs. 600

• As stated earlier, y represents the cost price of each chair.

 ∴  The cost price of each chair = Rs. 600

=> The cost price of 3 chairs = 3 × Rs. 600 = Rs. 1,800 (Answer)

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