Question

A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10 and each second class ticket costs Rs 3. What will another lot of 18 tickets in which the numbers of first class and second class tickets are interchanged cost?

Answer 1

let number of first class tickets be x
number of 2nd class tickets will be 18-x
according to question
$10x + 3(18 - x) = 110 \\ 10x + 54 - 3x = 110 \\ 7x = 110 - 54 \\ x = \frac{56}{7} = 8$
there are 8 first class ticket and 10 second class tickets
cost of tickets when the number of first class tickets and the second class tickets are interchanged is
$10 \times 10 + 8 \times 3 = 100 + 24 = 124$
Ans 124 rupees
please mark answer brainliest

Answer 2

A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10 and each second class ticket costs Rs 3 then -

1. Let the number of 1st class tickets be= x

And the number of second class ticket be = y

2. We know that

X+y= 18 And

X(10) + y(3) = 110 (given)

So, using X+Y= 18, we get,

X= 18-Y

3. So,

(18-Y) X 10 + 3 Y = 110

180 - 10Y + 3Y =110

180-110= 7Y

70/7 = Y =10 and x = 8

4. As per question, IF NUMBER OF X AND Y IS INTERCHANGED, THEN total cost = 10 (10) + 3(8) = 100 + 24 = 124