Question

a person buys 561 articles at 3200. he sells 5/11 part of the articles at 27% loss. At what % profit he should sell remaining articles so he will get nwither loss or gain?​

Answer 1

Step-by-step explanation: 22.63%

A person buys 561 articles at Rs 3200.

Cost of each article is Rs 3200/561 = Rs 5.70

He sells 5/11 th part of 3200.

That is 5/11 of 3200 = 255 articles.

He sells 255 articles at a loss of 27%.

∴ He sells them at Rs 5.70-27% = Rs 4.16 per article.

The selling price of 255 units is Rs 4.16× 255 = Rs 1060.80

Balance article is 561 - 255 = 306 articles.

The amount at which the remaining articles has to be sold is Rs 3200- Rs 1060.8 = Rs 2139.20

The buying price of each article is Rs 3200/561 = Rs 5.70

The balance article selling price per unit would be Rs 2139.2/306 = Rs 6.99

∴ The profit is Rs 6.99- Rs 5.70 = Rs 1.29.

Percentage profit = Profit/Cost price ×100

                              = 1.29/5.7 ×100

                              = 22.63% .

Hope this helps.

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https://brainly.in/question/9266811

Answer 2

Given:

• Person buys 561 articles for Rs 3200.

• He sells 5/11 part of the articles at a loss of 27%.

To find :

The profit % at which he will sell remaining articles so he will get neither loss nor gain.

Solution :

∴Price of 561 articles = Rs 3200

⇒price of one article = Rs $\frac{3200}{561}$

 = Rs 5.70  :

Now ,the no of particles he sells for 27 % loss =

$\frac{5}{11} \times 561\\ = 255$

And the remaining  no of particles that he has to sell =

561-255 = 306 :

The cost of 255 particles =

$Rs 255\times 5.70\\=Rs 1454.54$

And 27% of Rs 1454.54 =

$\frac{27}{100} \times 1454.54\\=Rs 392.58$

So the money he got after selling the 255 articles at 27% loss

=  Rs (1454.54 - 392 )

= Rs 1061  :

So the amount of money he need now by selling the remaining 306 articles so that he will get neither loss nor profit at all

= Rs (3200 - 1061 )

= Rs 2139  ;

Hence the cost of each particle for the remaining 306 particles

=

$Rs \frac{2138}{306} \\=Rs 6.98$

∴% profit =

$\frac{Selling Price - Cost price}{Cost price} \times 100\\= \frac{6.98 - 5,70}{5.70} \times 100\\= 0.224\times 100\\= 22.4$

So the required profit % at which he had to sell the remaining particles is 22.4%.