Question

A person buys 935 article at rs 1800.If he sells 2/7 part of all articles at 20% profit.At which % loss remaining articles he has to sell so that there is no profit no loss

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :

Number of articles = 935

Cost of articles = 1800 rs

Sells 2/7 part at 20% profit.

To find :

% loss of remaining articles for no total profit or loss.

Solution :

It is given that

20 % profit is shared by 2/7 parts of 935 articles

As all articles = 935 , which has cost = 1800 rs

so

cost of 2/7 parts of article:

$\frac{1800 \times 2}{7} = \frac{3600}{7}$

So,

20% of cost of 2/7 parts of article = profit of 2/7 parts :

$\frac{3600 \times 20}{7 \times 100} = \frac{720}{7}$

So Sell price of 2/7 parts of article :

$\frac{3600}{7} + \frac{720}{7} = \frac{4320}{7} rs$

Similarly

Cost of remaining (5/7) parts :

$\frac{1800 \times 5}{7} = \frac{9000}{7} rs$

To get total 0 % loss and profit.

The profit in 2/7 parts must be compensated as loss in remaining 5/7 parts of articles.

So

Loss of 5/7 parts of articles = Profit of 2/7 parts of articles

So

Loss of 5/7 parts of particles :

$\frac{720}{7} rs$

% of loss in 5/7 particles :

$\frac{9000 \times x}{7 \times 100} = \frac{720}{7} \\ \\ x = \frac{720}{90} = \frac{72}{9} = 8$

So,

% loss of remaining 5/7 particles to make total 0% loss and profit :

= 8%