Question

A person can run on ground with a maximum speed of 6m/s the person stands on the rear end of food a train moving with constant velocity the length of train is 120m the man beigns to run at this maximum a capacity towards the front end reached the front end find the net displacement of the man w.r.t. ground by the time he reached back to rest and the velocity of train is 10m/s

Answer 1

Answer:

Explanation:

=> Here, It is given that,

Speed of a man = 6 m/s

Length of train = 120 m

Velocity of the train = 10 m/s

=> The man's displacement when it reaches the rear end with respect to train is equal to zero.  

=> Thus, The net displacement of man = the displacement of the train (when the man reaches back to its original rear position on the train)

=> Therefore, Time taken = 2( Time required to reach from rear end to front end)  {Where, time required to reach from rear end to front end = Length of train / Speed of a man}  

Time taken = 2 (120/6)  

= 40 sec

=> Displacement traversed by the train in 40 sec = velocity of the train / time taken

= 10 * 40  

= 400 m