Question

A person can see clearly objects between 15 and 100cm from his eye. The range of his vision if
he wears close fitting spetancles having a power of 0.8 diopter is​

Answer 1

Given:-

• V = infinite

Focal length, f = 1/p

= 100/0.8

= 125cn

To see the object before 15cm

v = 15

u = ?

1/v - 1/u = 1/f

1/15 - 1/u = 1/125

u = 17.04 cm

To see the object far away from 100cm

u = 100

v = ?

1/v - 1/u = 1/f

1/v - 1/100 = 1/125

v = 500 cm

HOPE IT HELPS

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