A person can swim in still water at 4 km/h. if the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
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S = d/t
t = d / [(S_p) + (S_w)]
t = 6 / [(4) + (-2)]
t = 6 / 2 = 3 hours
i hope it will help you
regards
t = d / [(S_p) + (S_w)]
t = 6 / [(4) + (-2)]
t = 6 / 2 = 3 hours
i hope it will help you
regards
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