A person can swim with a velocity of 10km/hr relative to water.In an attempt to cross a river by the shortest path he starts off at an angle of sin^(-1)((12)/(13)) to the water current.The flow of water is at the rate of :
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Explanation:
Let the angle of the swimmer be e w.r.t the horizontal
cosθ=
AB
OA
=
V
s
V
w
=
10
5
⇒cosθ=1/2
⇒θ=60
o
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