A person can throw a stone to a maximum horizontal distance of h. the greatest height to which he can throw the stone
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Heya!!Here is your answer friend ⤵⤵
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⏪Maximum height - it is the maximum vertical distance attained by the projectile above the horizontal plane of projection .
⏪The maximum height is given by ,
![v {}^{2} - u {}^{2} = 2as \\ (0) {}^{2} - (u \: sin \: a) {}^{2} = 2( - g)hm \\ hm \: = \frac{u {}^{2}sin {}^{2}a }{2g} v {}^{2} - u {}^{2} = 2as \\ (0) {}^{2} - (u \: sin \: a) {}^{2} = 2( - g)hm \\ hm \: = \frac{u {}^{2}sin {}^{2}a }{2g}](https://tex.z-dn.net/?f=v+%7B%7D%5E%7B2%7D++-+u+%7B%7D%5E%7B2%7D++%3D+2as+%5C%5C+%280%29+%7B%7D%5E%7B2%7D++-+%28u+%5C%3A+sin+%5C%3A+a%29+%7B%7D%5E%7B2%7D++%3D+2%28+-+g%29hm+%5C%5C+hm+%5C%3A++%3D++%5Cfrac%7Bu+%7B%7D%5E%7B2%7Dsin+%7B%7D%5E%7B2%7Da++%7D%7B2g%7D+)
Here , Hm = maximum height
V= final velocity
U= initial velocity.
Hope it helps you ✌✌
↔↔↔↔↔↔↔↔↔↔↔↔↔↔
⏪Maximum height - it is the maximum vertical distance attained by the projectile above the horizontal plane of projection .
⏪The maximum height is given by ,
Here , Hm = maximum height
V= final velocity
U= initial velocity.
Hope it helps you ✌✌
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