Question

A person can walks first 10 km North and 20 km east then the resultant vector is
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Answer 1

Answer:

20i+10j where i is unit vector along x axis and j is unit vector along y axis.

Explanation:

Man walks 10km North first so the vertical displacement is 10km upwards and then he walks 20km East so horizontal displacement is 20km. Therefore 20i + 10j is the resultant vector whose magnitude is

$\sqrt{ {20}^{2} + {10}^{2} } = 22.36$