A person cannot see object nearer than 50cm from his eyes while a person with normal vision can see object up to 25cm from his eyes. Find the nature, focal length and the power of the correcting lens for the defective vision
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nature-----》 convex lens
take v = -50 cm
u= -25cm
use,
1/f = 1/v- 1/u
1/f = 1/ -50 +1 /25
1/f = 1-2/ -50
f = 50 cm
use
p= 1/f in m
p = 100/ 50
p= 2 diopter
p=
take v = -50 cm
u= -25cm
use,
1/f = 1/v- 1/u
1/f = 1/ -50 +1 /25
1/f = 1-2/ -50
f = 50 cm
use
p= 1/f in m
p = 100/ 50
p= 2 diopter
p=
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