A person cannot see objects clearly which are
placed before 40 cm from him, the power of the
lens to correct the vision is
A
+2.5 D
B
+1.5 D
C
+6.6 D
D
+3D
Answers
Answered by
0
That lens should be given to the person which forms the image of an object at infinity at distance 40 cm in front of the eye.
Hence, u=−∞ and v=−40cm
Now,
f1=v1−u1
⟹f1=40−1−−∞1
⟹f=−40cm
P=f(cm)100=40−100=
⟹P=−2.5D
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Answered by
1
Answer:
+2.5 D
Step-by-step explanation:
Because this lens is not either more or not either less so u can see with this number of lens from placed before 40cm from him
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