Question

a person carries rs 165 in the form of currency notes of denominations, rs 5,rupees 10&rs 20 in the ratio of 3:2:1, what is the value of currency notes of rs. 20 denominations

Answer 1

$\mathfrak{\huge{Answer:}}$

$\mathbb{GIVEN}$

Total amount of money the person carries = Rs. 165

Denominations of money the person carries = Rs. 5, Rs. 10, Rs. 20

Ratio of denominations = 3:2:1

$\mathbb{TO\:FIND}$

The value of currency notes of Rs. 20 denominations

$\mathbb{METHOD}$

Let the $\bf{number}$ of Rs. 5, Rs. 10 and Rs. 20 denominations be = 3x, 2x, and 1x respectively

Now, the $\bf{value}$ of Rs. 5 notes = 5 × 3x = $\tt{15x}$

The $\bf{value}$ of Rs. 10 notes = 10 × 2x = $\tt{20x}$

The $\bf{value}$ of Rs. 20 notes = 20 × 1x = $\tt{20x}$

When we'll add these all values together, we'll get Rs. 165 ( the total value is given to be = Rs. 165 )

=》 15x + 20x + 20x = 165

=》 55x = 165

=》 x = 3

The $\bf{value}$ of Rs. 5 notes = 5 × 3x = 5 × 3(3) = $\tt{Rs. 45}$

The $\bf{value}$ of Rs. 10 notes = 10 × 2x = 10 × 2(3) = $\tt{Rs. 60}$

The $\bf{value}$ of Rs. 20 notes = 20 × 1x = 20 × 3 = $\tt{Rs. 60}$

Thus, the final answer will be $\sf{\huge{Rs.\:60}}$