Question

a person carrying 10 bricks each of mass 2.5kg on his head moves to a height 20 m in 50s. Calculate power spent in carrying bricks by the person​

Answer 1

mass of each brick = 2.5 of

mass of 10 bricks = 2.5 x 10 = 25 lg

g = 10 m/ s

time = 5 second

height = 20 meter

power = work / time

mgh/ t

25x10x20/5 = 100 watt

it may help you

Answer 2

$here \: is \: your \: answer \\ mass \: of \: each \: brick = \: 2.5kg \\ so \: mass \: of \: 10 \: bricks \: = \: (2.5 \times 10)kg = \: 25kg \\ let \: gravitational \: force \: on \: his \: head \: = \: 10m {s}^{ - 2} \\ given \: time \: = \: 50s \: \\ given \: height \: = \: 20m\\ a.t.q \\ power \: spend \: in \: carrying \: bricks \: by \: person \: = \: \frac{work \: done}{time}.........eq \: (i) \\ work \: done \: = \: m \times g \times h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 25 \times 10 \times 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 5000n..........eq \: (ii) \\ putting \: value \: of \: eq(ii) \: in \: eq(i) \\ power \: = \: \frac{5000}{50} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 100watt \\ so \: power \: spent \: in \: carrying \: bricks \: by \: the \: person \: is \: 100watt. \\ \\ plz \: mark \: it \: as \: brainlilest.........$