A person carrying a bucket of water walks on a horizontal road with uniform velocity. What is the work done by him if the road is smooth?
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No work is done by him, since the direction of displacement is perpendicular to the direction of the applied force (which is the weight of the bucket of water acting downwards, in this case) i. e theta =0°.so cos theta = cos90° = 0
Therefore, work done
= F * d * 0
= 0. Hope this helps :)
No work is done by him, since the direction of displacement is perpendicular to the direction of the applied force (which is the weight of the bucket of water acting downwards, in this case) i. e theta =0°.so cos theta = cos90° = 0
Therefore, work done
= F * d * 0
= 0. Hope this helps :)
raven3:
please mark it as the brainliest if it helps :)
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