Question

A person chooses a date at random in November for a
party. Find the
probability that he chooses.

(i)Monday
(ii)Wednesday
(iii)Friday
(iv)Saturday (or) Sunday
​

Answer 1

Answer:

(i)4/30 i.e,2/15

(ii)4/30 i.e,2/15

(iii)5/30 i.e,1/6

(iv)5/30 i.e,1/6

(v)4/30 i.e,2/15

Answer 2

Answer:

▂▃▅▓▒░☆Answer☆░▒▓▅▃▂

(i) 2/15

(ii) 2/15

(iii) 1/6

(iv) 3/10

Step-by-step explanation:

A person chooses a date at random in November

Let 'S' be the Sample space.

∴ n(S) = 30 ...(November has total 30 days)

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(i) Event A: He chooses Monday.

There are total 4 Mondays in the month of November. ...(Given)

∴ n(A) = 4

Now,

P(A) = n(A)/ n(S) ...(Formula)

= 4/30

∴P(A) = 2/15

Ans. The probability that he chooses Monday is

2/15.

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(ii) Event B: He chooses Wednesday.

There are total 4 Wednesdays in the month of November. ...(Given)

∴ n(B) = 4

Now,

P(B) = n(B)/ n(S) ...(Formula)

= 4/30

∴P(B) = 2/15

Ans. The probability that he chooses Wednesday is 2/15.

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(iii) Event C: He chooses Friday.

There are total 5 Fridays in the month of November. ...(Given)

∴ n(C) = 5

Now,

P(C) = n(C)/ n(S) ...(Formula)

= 5/30

∴P(C) = 1/6

Ans. The probability that he chooses Friday is

1/6.

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(iv) Event D: He chooses Saturday or Sunday.

There are total 5 Saturdays and 4 Sundays in the month of November. ...(Given)

∴ n(D) = 5+4 =9

Now,

P(D) = n(D)/ n(S) ...(Formula)

= 9/30

∴P(D) = 3/10

Ans. The probability that he chooses Saturday or Sunday is 3/10.

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