Question

A person clapped his hand near a cliff and hurt the echo after 5 sec. what is the distance of the cliff from the person if the speed of the sound v is taken as 340m/s

Answer 1

Heya..

Here's your answer......

The sound traveled from the place the person stood, to the cliff and then rebounded back to the person , so the person heard the resound/echo.

So the sound traveled twice the distance between him/her and the cliff.

Distance between cliff and person = 340 m/sec * 5 seconds / 2

      = 850 meters

Thanks...!!!

XD

Sorry baby 'wink'

Answer 2

Distance travelled by the sound = v X t
  = 346 X 5
  = 1730 m

In 5 s sound has to travel twice the distance between the cliff and the person . Hence, the distance between the cliff and the person = 1730 / 2
 = 865 m