A person clapped his hands near a cliff and heard the echo after 4s .what is the distance of the cliff from the person if the speed of the sound V is taken as three 346m/s.
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3
in 4s the sound travels twice between the person and the cliff once the original sound and the second is the echo
so the distance between the person and cliff =speed *time/2=346*4/2=692m
so the distance between the person and cliff =speed *time/2=346*4/2=692m
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5
The sound traveled from the place the person stood, to the cliff and then rebounded back to the person , so the person heard the resound/echo.
So the sound traveled twice the distance between him/her and the cliff.
Distance between cliff and person = 346 m/sec * 4 seconds / 2
= 692meters
So the sound traveled twice the distance between him/her and the cliff.
Distance between cliff and person = 346 m/sec * 4 seconds / 2
= 692meters
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