Question

A person clapped his hands near a cliffs and heard the echo after 5 s. what is the distance of the cliff from the person if the speed of the sound,v is taken as 346 m s-¹​

Answer 1

Answer:

865 m.

Step-by-step explanation:

Given ,

Speed of sound , v = 346 m s-¹

Time taken for hearing the echo ,

t = 5 s

Distance travelled by the sound

= v × t = 346 m s-¹ × 5 s = 1730 m

In 5 s sound has to travel twice the distance between the cliff and the person.Hence , the distance between the cliff and the person .

= 1730 m/2 = 865 m.

Answer 2

Answer:

Step-by-step explanation:

We know that,

Speedofsound,v=346ms-¹

Timetakenforhearingtheecho,

t=5s

Distancetravelledbythesound

=v×t=346ms-¹×5s=1730m

In5ssoundhastotraveltwicethedistancebetweenthecliffandtheperson.Hence,thedistancebetweenthecliffandtheperson.

=1730m/2=865m.

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